If `a, x, y, z, b` are in AP, then `x+y+z=15` and if `a,x,y,z, b` are in HP. then `1/x + 1/y + 1/z = 5/3`. Numbers `a, b` are

Given that x+y+z =15 when a,x,y,z,b are in A.P and 1/x+1/y+1/z=5/3 when a,x,y,z,b are in H.P .Then

(i) The value of x + y + z is 15. If a, x, y, z, b are in AP while the value of (1)/(x) + (1)/(y) + (1)/(z) " is " (5)/(3) . If a, x, y, z b are in HP, then find a and b (ii) If x,y,z are in HP, then show that log (x +z) + log (x +z -2y) = 2 log ( x -z) .

(i) The value of x + y + z is 15. If a, x, y, z, b are in AP while the value of (1)/(x) + (1)/(y) + (1)/(z) " is " (5)/(3) . If a, x, y, z b are in HP, then find a and b (ii) If x,y,z are in HP, then show that log (x +z) + log (x +z -2y) = 2 log ( x -z) .

Given that x+y+z=15w h e na ,x ,y ,z ,b are in A.P. and 1/x+1/y+1/z+=5/3w h e n a ,x ,y ,z ,b are in H.P.

If a, b, c are in AP and a^(1/x)=b^(1/y)=c^(1/z) prove that x, y, z are in AP.

If x, y, z are in A.P.; ax, by, cz are in GP. and 1/a, 1/b, 1/c are in A.P., then x/z+z/x is equal to

The value of x+y+z is 15 if a,x,y,z,b are in AP while 1/x+1/y+1/z is 5/3 if a,x,y,z,b are in HP ,then the value of a is

x+y+z = 15 if 9, x,y,z,a are in A.P., while (1)/( x) + ( 1)/( y) + ( 1)/( z) = ( 5)?( 3) if 9, x,y,z,a are in H.P., then the value of a will be :

If a, b a n d c are in A.P., a x ,b y ,a n dc z in G.P. and x,y,z in H.P. then prove that x/z+z/x=a/c+c/a .