The base BC of a triangle ABCis bisected at the point `(a, b)` and equation to the sides AB and AC are respectively `ax + by=1 and bx + ay = 1`. Equation of the median through A is

The base BC of a triangle ABC is bisected at the point (a, b) and equation to the sides AB and AC are respectively ax+by=1 and bx+ay=1 Equation of the median through A is:

The base BC of a triangle ABC is bisected at the point (a, b) and equation to the sides AB and AC are respectively ax+by=1 and bx+ay=1 Equation of the median through A is:

The side BC of a triangle ABC is bisected at D; O is any point in AD. BO and CO produced meet AC and AB in E and F respectively and AD is produced to X so that D is the mid-point of OX. Prove that AO:AX=AF:AB and show that FE||BC.

The side BC of a triangle ABC is bisected at D;o is any point in AD,BO and CO produced meet AC and AB in E and F respectively and AD is produced to X so that D is the mid-point of OX. Prove that AO:AX=AF:AB and show that FE|BC.

In an isosceles triangle ABC, the coordinates of the points B and C on the base BC are respectively (1, 2) and (2. 1). If the equation of the line AB is y= 2x, then the equation of the line AC is

In an isosceles triangle ABC, the coordinates of the points B and C on the base BC are respectively (1,2) and (2.1). If the equation of the line AB is y=2x, then the equation of the line AC is

In an isosceles triangle ABC, the coordinates of the points B and C on the base BC are respectively (1, 2) and (2. 1). If the equation of the line AB is y= 2x, then the equation of the line AC is

If the mid points of the sides BC, CA and AB of a triangle ABC are respectively (2,1) (-01,-2)and (3,3) then the equation of the side BC is