Recommended Questions
- logx=37. 288 then x=2xx1 0^(37) how ? please explain
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- log x=37.288 then x=3.92xx10^(37) how? please explain
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- log x=37.288 then x=2xx10^(37) how? please explain
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- (0.bar(63)+0.bar(37)) का मान है।
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- Solve For x and y : 71 x + 37 y = 253 , 37 x + 71 y = 28...
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- (-37) xx (-7) +(-37) xx (-3) =?
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- यदि y=3cos(logx)+4sin(logx) हो तो सिद्ध कीजिए x^(2)y(2)+xy(1)+y=0
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- The weights of 10 students (in kg) are given below:40, 35, 42, 43, 37,...
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- The value of (0.bar(63) + 0.bar(37)) is
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