Cos { 2 pi/2^64 - 1) cos{2^2 pi/(2^64-1)...

` Cos { 2 pi/2^64 - 1) cos{2^2 pi/(2^64-1)}.........cos{2^64 pi/(2^64 - 1)}` =

Cos { 2 pi/2^64 - 1) cos{2^2 pi/(2^64-1)}.........cos{2^64 pi/(2^64 - ...
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cos {2 (pi) / (2 ^ (64)) - 1) cos {2 ^ (2) (pi) / (2 ^ (64) -1)} dots ...
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(sin ^ (2) [64]) / (cos ^ (2) [26]) =?
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If sin^(-1)x+sin^(-1)y=pi/2 and sin2x=cos2y , then (a) x=pi/8+sqrt(...
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(64)^((1)/(3))[(64)^((1)/(3))-(64)^((2)/(3))]=?
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let x(1)=cos((pi)/(11))cos((2 pi)/(11))cos((3 pi)/(11))cos((4 pi)/(11)...
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cos ((pi) / (65)) cos ((2 pi) / (65)) cos ((4 pi) / (65)) cos ((8 pi) ...
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64. (cos A + cos B) ^ (2) + (sin A + sin B) ^ (2) =
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The value of x which satisfies 8^(1+cos x+cos^(2)x +….) = 64 in [-pi,...
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