If `z=1/(1-cos theta-i sin theta),` then `Re(z)` is a. `0` b. `1/2` c. `cot(theta/2)` d. `1/2 cot (theta/2)`

If z = (1)/(1 - cos theta - i sin theta), the Re (z)=

(1+cos 2 theta)/(sin 2 theta)=cot theta

If a=cos theta+i sin theta, then (1+a)/(1-a) is equal to ( i) cot((theta)/(2))( ii) cot theta( iii) i cot((theta)/(2))( iv )i tan((theta)/(2))

If z=1-cos theta+i sin theta, then |z|=2(sin theta)/(2) b.2(sin theta)/(2)c.2|(sin theta)/(2)|d.2|(cos theta)/(2)|

If a=cos theta+i sin theta, then (1+a)/(1-a)=(cot theta)/(2) b.cot theta c.i(cot theta)/(2)d*i(tan theta)/(2)

If (1 + z)/(1 - z) = cos 2theta + i sin 2theta , show that z = i tan theta .

(sin 2 theta)/(1-cos 2 theta)=cot theta

If z=cos theta+i sin theta, then the value of (z^(2n)-1)/(z^(2n)+1)(A)i tan n theta(B)tan n theta(C)i cot n theta(D)-i tan n theta

(1 - cos^(2)theta)cot^(2)theta