`1 + sec 20 =`

1 + sec20 =

sqrt3"cosec"20^(@) - sec20^@ =

The equation of motion of particle is S=at^(2) +bt+c .If the displcement after 1 sec is 20 m, velo0city after 2 sec is 30 m/ sec and the acceleration is 10m//se^(2) , then

sin 20^(@) (4 + sec 20^(@)) =

Show that sqrt(3)cosec 20^@ - sec 20^@= 4

The value of sqrt3"cosec"20^@ - sec 20^@ is equal to

sqrt2 "cosec"20^@ sec20^@ =

The rate constant of reaction 2 A + B rarr C is 2.57 xx 10^(-5) L "mole"^(-1) sce^(-1) after 10 sec , 2.65 xx 10^(-5) L "mole"^(-1)sec^(-1) after 20sec and 2.55 xx 10^(-5) L "mole"^(-1) sec^(-1) after 30 sec . The order of the reaction is :