Let `f(x)=((2008)^x+(2008)^(-x))/2,g(x)=((2008)^x-(2008)^(-x))/2` then prove that `f(x+y)=f(x)f(y)+g(x)g(y)`

Range of f(x)=(2008^(x)+2008^(-x))/(2) is

Let x=(2008)^(1004)+(2008)^(-1004) and y=(2008)^(1004)-(2008)^(-1004) then the value of x^(2)-y^(2)

If f(x)=(1)/(2)(3^(x)+3^(-x)),g(x)=(1)/(2)(3^(x)-3^(-x)) then f(x)g(y)+f(y)g(x)=

If f(x)=(1)/(2)[3^(x)+3^(-x)], g(x)=(1)/(2)[3^(x)-3^(-x)] then f(x)g(y)+f(y)g(x)=

If f(x) = 1/2 (3^x + 3^(-x)), g(x) = 1/2 (3^x - 3^(-x)) , then f(x) \ g(y)+f(y) \ g(x)=

Let f(x)=(2007^(x))/(2007^(x)+sqrt(2007)) Then find the value of quad 2007^(x)+sqrt(2007)(1)/(2)+f((2)/(2008))+f((3)/(2008))+...+f((2007)/(2008))

Let f(x) = (x+1)/(x-1), fof(x) =f^(2)(x), fofof(x) =f^(3)(x), fofofof(x) =f^(4)(x) ……. Then f^(2008) =

intf(x)dx= . . . . . . . +c,f(x)=|{:(2007,2008),(2007x,2008x):}|