A particle executes SHM from extreme position and covers a distance equal to half to its amplitude in 1 s.

A particle executing of a simple harmonic motion covers a distance equal to half its amplitude in on e second . Then the time period of the simple harmonic motion is

A particle executing of a simple harmonic motion covers a distance equal to half its amplitude in on e second . Then the time period of the simple harmonic motion is

The shortest distance travelled by a particle executing SHM from mean position in 2 s is equal to (sqrt(3)//2) times its amplitude. Determine its time period.

The shortest distance travelled by a particle executing SHM from mean position in 2 s is equal to (sqrt(3)//2) times its amplitude. Determine its time period.

The shortest distance travelled by a particle executing SHM from mean position in 2 s is equal to (sqrt(3)//2) times its amplitude. Determine its time period.

Velocity at mean position of a particle executing SHM is v. Velocity of the particle at a distance equal to half of the amplitude will be

Velocity at mean position of a particle executing SHM is v. Velocity of the particle at a distance equal to half of the amplitude will be

Velocity at mean position of a particle executing S.H.M. is v , they velocity of the particle at a distance equal to half of the amplitude