The value of `cosA cos2A cos2^2A......cos(2^(n-1)A)`, where `A in R` may be . (A) 1 (B) `-1` (C) 2 (D) `sin2^n A/(2^n sinA)`

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Prove that : cos A cos 2A cos 2^2 A cos 2^3 A........ cos 2^(n-1) A= (sin 2^n A)/(2^n sinA) .

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