A block of mass `10kg` is released on a fixed wedge inside a cart which is moved with constant velocity `10m//s` towards right. Take initial velocity of block with respect to cart zero. Then work done by normal reaction (with respect to ground) on block in two second will be `:(g=10 m//s^(2))`.

A block of mass 10 kg is released on a fixed wedge inside a cart which is moving with constant velocity 10 ms^(-1) towards right. There is no relative motion between block and cart. Then work done by normal reaction on block in two seconds from ground frame will be ( g=10 ms^(-2) )

A block of mass 10 kg is released on a fixed wedge inside a cart which is moving with constant velocity 10 ms^(1) towards right. There is no relative motion between block and cart. Then work done by mormal reaction on block in two seconds from ground frame will be (g=10 ms^(1))

Blocks shown in figure moves with constant velocity 10 m/s towards right. All surgaces in contact are rough. The friction force applied by B on A is :-

Blocks shown in figure moves with constant velocity 10 m/s towards right. All surgaces in contact are rough. The friction force applied by B on A is :-

Blocks shown in figure moves with constant velocity 10 m/s towards right. All surgaces in contact are rough. The friction force applied by B on A is :-

A block of mass m = 10 kg is released from the top of the smooth inclined surface of a wedge which is moving horizontally toward right at a constant velocity of u = 10 m/s. Inclination of the wedge is theta=37^(@) . Calculate the work done by the force applied by the wedge on the block in two seconds in a reference frame attached to - (a) the ground (b) the wedge. [Take g=10 m//s^(2) ]

A block of mass 4kg is released from the top of a rough inclines plane of height 10 m . If velocity of the block is 10 m//s at the bottom of the inclined then work done by the friction force on the block will be

A block of mass 10 kg is released on rough incline plane. Block start descending with acceleration 2m//s^(2) . Kinetic friction force acting on block is (take g=10m//s^(2) )

A block of mass 10 kg is released on rough incline plane. Block start descending with acceleration 2m//s^(2) . Kinetic friction force acting on block is (take g=10m//s^(2) )

Block of mass 10 kg is moving on inclined plane with constant velocity 10 m/s. The coedfficient of kinetic friction between incline plane and block is :-