If `(1+cos theta-i sin theta)(1+cos2 theta+i sin2 theta)=x+iy` then `x^(2)+y^(2)=`

If (1 + cos theta - isin theta) ( 1+ cos 2 theta + isin 2 theta) = x +iy then x^(2) + y^(2) =

If (1 + cos theta + isin theta) (1 + cos 2 theta + isin 2theta) = x + iy then y =

2(cos theta+cos2 theta)+(1+2cos theta)sin2 theta=2sin theta

(sin theta+sin2 theta)/(1+cos theta+cos2 theta)=tan theta

(sin theta+sin2 theta)/(1+cos theta+cos2 theta)=tan theta

Simplify ((1 + cos 2 theta + i sin 2 theta)/(1 + cos 2 theta - i sin 2 theta))^(30)

If (cos theta + i sin theta)(cos 2 theta +i sin 2 theta ) …(cos n theta + i sin n theta)=1 then the value of theta is (m are integers)-

If x+i y=(1)/(1+cos theta+i sin theta) then x^(2)