The coefficients of three consecutive terms in the expansion of `(1+x)^n` are in the ratio `182:84:30`. prove that `n=18`

The coefficients of three consecutive terms in the expansion of (1+x)^n are in the ratio 1:7:42 , then n=

The coefficients of three consecutive terms in the expansion of (1+x)^(n) are in the ratio 1:7:42. Find n.

The coefficients of three consecutive terms in the expansion of (1+a)^(n) are in the ratio 1:7:42. Find n.

The coefficient of three consecutive terms in the expansion of (1 + x)^(n ) are in the ratio 1 : 6 : 30. Find n.

The coefficients of three consecutive terms in the expansion of. (1+a)^n are in the ratio 1: 7: 42. Find n.

The coefficients of three consecutive terms in the expansion of (1+a)^n are in the ratio 1: 7 : 42. Find n.

The coefficients of three consecutive terms in the expansion of (1+a)^n are in the ratio : 6: 33: 110. Find n.

If the coefficients of three consecutive terms in the expansion of (1 + x)^(n) are in the ratio 1 : 3 : 5, then show that n = 7.

The coefficients of three consecutive terms in the expansion of (1 + a)^n are are in the ratio 1: 7: 42 Find n.