A simple pendulum undergoes `20` oscillation's in `30` seconds. What is the percentage error in the value of acceleration due to gravity provided length of pendulum is `55cm`, least count of rmeasurement of time and length are `1 s` and `1mm` respectively

The effective length of a simple pendulum is 1 m. The pendulum completes 20 oscillations in 40 s. What is the value of acceleration due to gravity at that place?

If the length of a simple pendulum is recorded as (90 +- 0.2)cm and period as (1.9 +- 0.02)s , the percentage fo error in the measurement of acceleration due to gravity is

Consider a simple pendulum. The period of oscillation of the simple pendulum depends on its length and acceleration due to gravity. Then the expression for its time period is

If a Seconds pendulum is moved to a planet where acceleration due to gravity is 4 times, the length of the second's pendulum on the planet should be made

If a Seconds pendulum is moved to a planet where acceleration due to gravity is 4 times, the length of the second's pendulum on the planet should be made

A simple pendulum makes 20 oscillations in one second on the surface of the earth. Determine the time period of the simple pendulum on the surface of a planet where the acceleration due to gravity is one fourth of the acceleration due to gravity on the surface of the earth .