Two metal plates are separated by a distance `d` in a parallel plate condenser. A metal plate of thickness `t` and of the same area is inserted between the condenser plates. The value of capacitance increases by ….times.

Two metal plates form a parallel plate condenser. The distance between the plates in d. Now a metal plate of thickness d/2 and of same area is inserted completely between the plates, the capacitance

Two metal plates form a parallel plate capacitor. The distance between the plates is d. A metal sheet of thickness d/2 and of the same area is indroduced between the plates. What is the ratio of the capacitances in the two cases?

A metal plate of thickness half the separation between the capacitor plates of capacitance C is inserted. The new capacitance is.

Two identical metal plates separated by a distance 'd' form parallel plate capacitor (air gap) of capacitance C. A metal sheet of thickness (d/2) and same dimensions is inserted between the plates ,so that the air gap is separated into two equals parts. The new capacity of the system will be:

The distance between the plates fo a parallel plate capacitor is d. A metal plate of thickness d//2 is placed between the plates, what will be the new capacity ?

The separation between the two plates of a parallel plate capacitor is d. A metal plate of equal area and of thickness (d)/(2) is inserted between the two plates. The ratio of the capacitances after and before this insertion is

The distance between the plates of a parallel plate condenser is d. If a copper plate of same area but thickness d/2 is placed between the plates then the new capacitance will become -