The equation of the straight line passing through the point `(4, 3)` and making intercepts on the co-ordinate axes whose sum is `-1` is
(a)`x/2-y/3=1` and `x/-2+y/1=1`         (b)`x/2-y/3=-1` and `x/-2+y/1=-1`
(c)`x/2+y/3=1` and `x/2+y/1=-1`         (d)`x/2+y/1=-1` and `x/-2+y/1=-1`

Domain of [ x ] + x is : 1)   R   2 )   z   3 ) R - 2

If 2^(2x-1) = 1/ 8^(x-3) then find x = ? a)   -2   (b)   -1   (c)   2   (d) 3

Equation of the line passing through (1,2) and parallel to the line y=3x-1 is............. A) y+2 =x+1 B) y+2=3(x+1) C) y-2 =3 (x-1) D) y-2 =x-1

Find the value of   [ ( x/y - 1 ) / ( 1 - x/y ) ] ( a )   0   ( b )   1   ( c )   -1   ( d )   x/y

If   2^x - 4^(2x-1) = 0 , then x = (a)   2/3   (b)   -2/3   (c)   3/2   (d)   -3/2

(i) Find the equations of the straight line passing through the point (2,3,-1) and is perpendicular to the lines : ( x-2)/(2) = (y + 1)/(1) = (z - 3)/(-3) and (x - 3)/(1) = (y + 2)/(1) = (z - 1)/(1) . (ii) Find the equation of the line which intersects the lines : (x + 2)/(1) = (y - 3)/(2) = (z + 1)/(4) and (x - 1)/(2) = (y - 2)/(3) = (z - 3)/(4) Perpendicular and passes through the point (1,1,1) .

Evaluate : lim_( x -> 0 ) (( 1 - sqrt(1 - x^2 ) ))/ x^2 ( a ) 1/2 ( b )   2   ( c )   1   ( d )   -1

Evaluate : lim_( x -> 0 ) (( 1 - sqrt(1 - x^2 ) ))/ x^2 ( a ) 1/2 ( b )   2   ( c )   1   ( d )   -1

The equation of the curve passing through origin, whose slope at any point is (x(1+y))/(1+x^2) , is (A) (1+y)^2-x^2=1 (B) x^2+(y+1)^2=1 (C) (x+y)y=1-x^2 (D) x=ye^((1+y))

The equation of the curve passing through origin, whose slope at any point is (x(1+y))/(1+x^2) , is (A) (1+y)^2-x^2=1 (B) x^2+(y+1)^2=1 (C) (x+y)y=1-x^2 (D) x=ye^((1+y))