A body of mass `m_(1) = 4kg moves at `5 hat(i) ms^(-1)` and another body of mass `m_(2) = 2kg` moves at `10hat(i)ms^(-1)`. The kinetic energy of center of mass is

A body of mass m_1=4 kg moves at 5 hati m//s and another body of mass m_2=2 kg moves at 10 hati m//s . The kinetic energy of center of mass is

A body of mass 50 kg has a momentum of 3000 kg ms^(-1) . Calculate: The kinetic energy of the body.

A body of mass 5 kg moves along X-axis with 2ms^(-1) A second body of mass 10 kg moves along y-axis with velocity sqrt3 ms^(-1) . They collide at the origin and stick together. The velocity of the combined mass is :

The linear momentum of a body of mass 2 kg is 16 kg ms^-1 . What is its kinetic energy?

When a body of mass m_(1) moving with uniform velocity 40 ms^(-1) collides with another body of mass m_(2) at rest, then the two together begin to move with uniform velocity of 30 ms^(-1) . The ratio of the masses (i.e., m_(1)//m_(2) ) of the two bodies will be

A body of mass 5 kg moving with a velocity of 6 m s^(-1) collide with another body of mass 2 kg which is at rest. Afterwards they move in the same direction as before. If the velocity of the body of mass 2 kg 10 ms^(-1) , find the velocity and kinetic energy to the body of mass 5 kg.