GIVEN : `P Q R S` is a quadrilateral. `P Q` is its longest side and `R S` is its shortest side. TO PROVE : (i) `/_R >/_P` (ii) `/_S>/_Q` CONSTRUCTION : Join `P R` and `Q Sdot` Figure

In Figure, P Q R S is a quadrilateral. P Q is its longest side and R S is its shortest side. Prove that /_R >\ /_P\ a n d\ /_S >\ /_Q .

In Figure, P Q R S is a quadrilateral. P Q is its longest side and R S is its shortest side. Prove that /_R > /_P a n d /_S > /_Q Given : P Q R S is a quadrilateral. P Q is its longest side and R S is its shortest side. To Prove : (i) /_R > /_P (ii) /_S > /_Q Construction : Joint P R a n d Q S

In Figure, P Q R S is a quadrilateral and T\ a n d\ U are respectively points on P S and R S such that P Q=R Q ,\ /_P Q T=/_R Q U\ a n d\ /_T Q S=/_U Q Sdot Prove that Q T=Q Udot

In Figure, P Q R S is a quadrilateral in which diagonals P R\ a n d\ Q S intersect in O . Show that : (i) P Q+Q R+R S+S P > P R+Q S (ii) P Q+Q R+R S+S P<2(P R+Q S)

In Figure, P Q R S is a quadrilateral in which diagonals P R and Q S intersect in O . Show that P Q+Q R+R S+S P > P R+Q S PQ+QR+RS+SP<2 (PR+QS) Figure

If P is the husband of Q and R is the mother of S and Q, what is R to P?

In Figure, T is a point on side Q R of P Q R and S is a point such that R T=S Tdot Prove That : P Q+P R > Q S

In Figure, if quadrilateral P Q R S circumscribes a circle, then P D+Q B= (a) P Q (b) Q R (c) P R (d) P S

In P Q R , S is any point on the side Q R . Show that P Q+Q R+R P >2P S

In Delta P Q R , if P Q=Q R and L ,M and N are the mid-points of the sides P Q ,Q R and R P respectively. Prove that L N=M Ndot