A ray of light is sent along the line `2x-3y=5.` After refracting across the line `x+y=1` it enters the opposite side after torning by `15^0` away from the line `x+y=1` . Find the equation of the line along which the refracted ray travels.

A ray of light is sent along the line 2x-3y=5. After refracting across the line x+y=1 it enters the opposite side after torning by 15^(@) away from the line x+y=1 . Find the equation of the line along which the refracted ray travels.

A ray of light is sent along the line x-6y = 8 After refracting across the line x + y = 1 it enters the opposite side after turning by 15^(@) away from the line x+ y =1 .Find the equation of the line along which the refracted ray travels .

A ray of light travelling along the line x+y=1 is incident on the x-axis and after refraction it enters the other side of the x-axis by turning 30^0 away from the x-axis. The equation of the line along which the refracted ray travels is

A ray of light traveling along the line x+y=1 is inclined on the x-axis and after refraction,it enters the other sides of the X- axis by turning 15^(@) away from the x-axis.The equation of the line along which the refraction ray travels

If a ray travelling the line x = 1 gets reflected the line x+y=1 then the equation of the line along which the reflected ray travels is

A ray of light travelling along the line x+y=1 is incident on the X - axis and after refraction the other side of the X - axis by turning pi//6 by turning away from the X - axis .The equation of the line along which the refracted ray travels is

A beam of light is sent along the line x-y=1 , which after refracting from the x-axis enters the opposite side by turning through 30^0 towards the normal at the point of incidence on the x-axis. Then the equation of the refracted ray is (a) (2-sqrt(3))x-y=2+sqrt(3) (b) (2+sqrt(3))x-y=2+sqrt(3) (c) (2-sqrt(3))x+y=(2+sqrt(3)) (d) y=(2-sqrt(3))(x-1)

514 Abeam of light is sent along the line x-y -1,which after refracting from the x-axis enters the opposite side tuming through 300 towards the normal at the point of incidence on the x-axis.Then the equation of the refracted ray is

A ray of light is sent along the line x-2y-3=0 upon reaching the line 3x-2y-5=0, the ray is reflected from it. Find the equation of the line containing the reflected ray.