Factorize: `(2x-3y)^3+(4z-2x)^3+(3y-4z)^3`

Similar Questions

Explore conceptually related problems

Factorize: (3x-2y)^3+(2y-4z)^3+(4z-3x)^3

Factorize: (3x-2y)^(3)+(2y-4z)^(3)+(4z-3x)^(3)

Factors of (2x - 3y) ^(3) + ( 3y - 5z) ^(3) + ( 5z - 2x) ^(3) are:

Factorize: (x/2+y+z/3)^3+\ \ (x/3-(2y)/3+z)^3+(-(5x)/6-y/3-(4z)/3)^3

Factorize: ((x)/(2)+y+(z)/(3))^(3)+((x)/(3)-(2y)/(3)+z)^(3)+(-(5x)/(6)-(y)/(3)-(4z)/(3))^(3)

Factorise : ((x)/(2)+y+(z)/(3))^(3)+((x)/(3)-(2y)/(3)+z)^(3)-((5x)/(6)+(y)/(3)+(4z)/(3))^(3)

Prove that 64(x+y+z)^3-(2x+y+z)^3-(x+2y+z)^3-(x+y+2z)^3=3(3x+3y+2z)(3x+2y+3z)(2x+3y+3z)

Solve the following equations, using inverse of a matrix: {:(2x-3y+5z=1),(3x+2y-4z=-5),(x+y-2z=-3):}

2x+3y+3z=5 x-2y+z=-4 3x-y-2z=3

x-y=3 2x+3y+4z=17 y+2z=7