If `(x+y)^(2)=2(x^(2)+y^(2))and(x-y+lamda)^(2)=4,lamdagt0,` then `lamda` is equal to :

If log_lamdax.log_5lamda=log_x5,lamda ne1,lamdagt0 , then x is equal to

If log_lamdax.log_5lamda=log_x5,lamda ne1,lamdagt0 , then x is equal to

If log_lamdax.log_5lamda=log_x5,lamda ne1,lamdagt0 , then x is equal to

If log_lamdax.log_5lamda=log_x5,lamda ne1,lamdagt0 , then x is equal to

If log_lamdax.log_5lamda=log_x5,lamda ne1,lamdagt0 , then x is equal to

If e^(y)+xy=e," then: "[(d^(2)y)/(dx^(2))]_(x=0) is e^(lamda) then numerical quantity lamda should be equal to

Ilf the circle x^(2)+y^(2)=2 and x^(2)+y^(2)_4x-4y+lamda=0 have exactly three real common tangents then lamda=

lf the circle x^(2)+y^(2)=2 and x^(2)+y^(2)-4x-4y+lamda=0 have exactly three real common tangents then lamda=

x ^(2) (lamda ^(2) - 4 lamda + 3) +y ^(2) (lamda ^(2) - 6 lamda +5) =1 will represent an ellipse if lamda lies in the interval