If the area enclosed between the curves `y=kx^2` and `x=ky^2`, where `kgt0`, is 1 square unit. Then k is: (a) `1/sqrt(3)` (b) `sqrt(3)/2` (c) `2/sqrt(3)` (d) `sqrt(3)`

If the area enclosed between the curves y=kx^(2) and x=ky^(2), where k>0, is 1 square unit.Then k is: (a) (1)/(sqrt(3)) (b) (sqrt(3))/(2) (c) (2)/(sqrt(3))(d)sqrt(3)

The area enclosed between the curves y = x^(3) and y = sqrt(x) is

The area enclosed between the curves y = x^(3) and y = sqrt(x) is

The area enclosed between the curves y=ax^(2) and x=ay^(2)(a>0) is 1 sq.unit, value of a is (1)/(sqrt(3)) (b) (1)/(2)(c)1(d)(1)/(3)

Area bounded between the curves y=sqrt(4-x^(2)) and y^2=3|x| in square units is

The area enclosed by the curves y=sinx+cosx and y=|cosx−sinx| over the interval [0,pi/2] is (a) 4(sqrt2-1) (b) 2sqrt2(sqrt2-1) (c) 2(sqrt2+1) (d) 2sqrt2(sqrt2+1)

The value of sqrt(3-2\ sqrt(2)) is (a) sqrt(2)-1 (b) sqrt(2)+1 (c) sqrt(3)-sqrt(2) (d) sqrt(3)+\ sqrt(2)

The area bounded by the curves y = - x^(2) + 3 and y = 0 is a) sqrt(3)+1 b) sqrt(3) c) 4sqrt(3) d) 5sqrt(3)

The area bounded by the curve x^2 = ky,k>0 and the line y=3 is 12 unit^2 . Then k is (A) 3 (B) 3sqrt3 (C) 3/4 (D) none of these

A pair of tangents is drawn to a unit circle with center at the origin and these tangents intersect at A enclosing an angle of 60^0 . The area enclosed by these tangents and the arc of the circle is (a) 2/(sqrt(3))-pi/6 (b) sqrt(3)-pi/3 (c) pi/3-(sqrt(3))/6 (d) sqrt(3)(1-pi/6)