The relation between the displacement x and the time t for a body of mass 2 kg moving under the action of a force is geven by `x=t^(3)//3` , where x is in metre and t in second ,Calculate the ork done by the body in first 2 seconds.

The relation between the displaement x and the time t for a body of mass 2 kg moving under the action of a force is given by x=t^3//3 , where x is in metre and t in second . Calculate the work done by the body in the first 2 seconds .

Under the action of force, 2 kg body moves such that its position x as a function of time t is given by x=(t^(3))/(3) , x is in metre and t in second. Calculate the work done by the force in the first 2 second.

The displacement of a partcle is given by x=(t-2)^(2) where x is in metre and t in second. The distance coverred by the particle in first 3 seconds is

The distance x moved by a body of mass 0.5 kg under the action of a force varies with time t as x(m)=3t^(2)+4t+5 Here, t is expressed in second. What is the work done by the force in first 2 seconds?

The distance x moved by a body of mass 0.5 kg under the action of a force varies with time t as x(m)=3t^(2)+4t+5 Here, t is expressed in second. What is the work done by the force in first 2 seconds?

Under the action of a force, a 2 kg body moves such that its position x as a function of time is given by x =(t^(3))/(3) where x is in metre and t in second. The work done by the force in the first two seconds is .