`(16)^(2)+(27)^(2)-24=?^(2)`

The value of 9+(16)/(2!)+(27)/(3!)+(42)/(4!)+……infty is

The value of 9+(16)/(2!)+(27)/(3!)+(42)/(4!)+……infty is

16a^(2)-24a+2bc+9-b^(2)-c^(2)

Domain of (16x^(2)-12x+9)/(16x^(2)+24x+9) is :

Factorise the using the identity a ^(2) + 2 ab + b ^(2) = (a + b) ^(2) 9x ^(2) + 24 x + 16

(64x^(3)-:27backslash a^(-3))^(-2/3)= a.(9ax)/(16) b.(9)/(16ax) c.(9)/(16x^(2)a^(2)) d.(3)/(4)x^(-2)a^(-2)

Facorise the following (i) 9x^(2)+4y^(2)+16z^(2)+12xy-16yz-24xz (ii) 25x^(2)+16y^(2)+4z^(2)-40xy+16yz-20xz (iii) 16x^(2)+4y^(2)+9z^(2)-16xy-12yz+24xz