Let `C_1 : x^2 + y^2-2x = 0` and `C_2 : x^2 + y^2-2x-1=0.` If `P` is a point on `C_2` and PA and PB are the tangents to the circle `C_1` then angle between these two tangents is

The equations of two circles are x^(2)+y^(2)+2 lambda x+5=0 and x^(2)+y^(2)+2 lambda y+5=0 .P is any point on the line x-y=0 .If PA and PB are the lengths of the tangents from P to the two circles and PA=3 them PB=

The equations of two circles are x^(2)+y^(2)+2 lambda x+5=0 and x^(2)+y^(2)+2 lambda y+5=0.P is any point on the line x-y=0. If PA and PB are the lengths of the tangent from Ptothe circles and PA=3 then find PB.

x^2+y^2+2lambdax+5=0 and x^2+y^2+2lambday+5=0 are two circles. P is a point on the line x-y=0. If PA and PB are the lengths of the tangents from P to the two cricles and PA=3, then PB=

x^2+y^2+2lambdax+5=0 and x^2+y^2+2lambday+5=0 are two circles. P is a point on the line x-y=0. If PA and PB are the lengths of the tangents from P to the two cricles and PA=3, then PB=

If y+c=0 is a tangent to the circle x^2+y^2-6x-2y+1=0 at (a,4) then

A line y=2x+c intersects the circle x^(2)+y^(2)-2x-4y+1=0 at P and Q. If the tangents at P and Q to the circle intersect at a right angle,then |c| is equal to

From the point P(4,-4) tangents PA and PB are drawn to the circle x^(2)+y^(2)-6x+2y+5=0 whose centre is C then Length of AB

Let C_(1) and C_(2) be the circles x^(2) + y^(2) - 2x - 2y - 2 = 0 and x^(2) + y^(2) - 6x - 6y + 14 = 0 respectively. If P and Q are points of intersection of these circles, then the area (in sq. units ) of the quadrilateral PC_(1) QC_(2) is :

If tangent at (1, 2) to the circle C_1: x^2+y^2= 5 intersects the circle C_2: x^2 + y^2 = 9 at A and B and tangents at A and B to the second circle meet at point C, then the co- ordinates of C are given by