In triangle ABC, AB = 5. BC = 9 and AC =7. The value of `tan((A-B)/2)/tan((A+B)/2)` is

In an isosceles triangle ABC. AB = BC = 10 cm and BC = 18 cm . Find the value of : tan ^(2) C - sec ^(2)B +2

In triangle ABC, if r_(1)=3r, then the value of tan((A)/(2))(tan((B)/(2))+tan((C)/(2))) is equal to

In /_\ABC , right angled at B, AB=3 , BC=4 and CA=5 . Then value of tan^2C+1 is:

In a triangle ABC,B=90^(@) then the value of tan((A)/(2))=

In a triangle ABC,B=90^(@) then the value of tan((A)/(2))=

In an isosceles triangle ABC if AB = AC= 10 cm and BC =12 cm, find the values of tan /_ACB and cosec /_ACB .

In triangle ABC, AB = AC = 15 cm and BC = 18 cm. Find : tan^2B - sec^2 B+2

In triangle ABC ,prove that the maximum value of tan(A)/(2)tan(B)/(2)tan(C)/(2)is(R)/(2s)

In triangle ABC, tan A + tan B + tan C = 6 and tanA tanB = 2, then the values of tan A, tan B, tan C are, respectively:

In triangle ABC , tan A +tan B +tan C =6 and tan A tan B =2 , then the values of tan A , tan B , tan C are