At what point on the parabola `y^2=4x` the normal makes equal angle with the axes? (A) `(4,4)` (B) `(9,6)` (C) `(4,-4)` (D) `(1,+-2)`

The point on the parabola y^(2)=4 x , the normal makes equal angles with the axes is

A normal is drawn at a point " (x_(1),y_(1)) " of the parabola " y^(2) - 16x " and this normal makes equal angle with both "x" and "y" axes,Then point " (x_(1),y_(1)) " is (a) " (4,-4) ," (b) " (2,-8) " (c) " (4,-8) " (d) " (1,-4) "

The normal to parabola y^(2) =4ax from the point (5a, -2a) are

The normal to parabola y^(2) =4ax from the point (5a, -2a) are

The normals to the parabola y^(2)=4ax from the point (5a,2a) is/are

If a normal chord at a point on the parabola y^(2)=4ax subtends a right angle at the vertex, then t equals

If a normal chord at a point on the parabola y^(2)=4ax subtends a right angle at the vertex, then t equals

If a line x+ y =1 cut the parabola y^2 = 4ax in points A and B and normals drawn at A and B meet at C. The normals to the parabola from C other than above two meets the parabola in D, then point D is : (A) (a,a) (B) (2a,2a) (C) (3a,3a) (D) (4a,4a)