In a compound Carbond `=52.2%` , Hydrogen `=13%`, Oxygen `=34.8%` are present vapour density of the compound is 46. Calculate molecular formula of the compound ?

A compound contains 52.2% C and 13 % hydrogen and remaining percentage oxygen. If vapour density of the compound is 46, molecular formula is

A compound X consists of 4.8% carbon and 95.2% bromine by mass. If the vapour density of the compound is 252, what is the molecular formula of the compound?

A compound has the following percentage composition by mass : Carbon = 54.55%, Hydrogen = 9.09% and Oxygen = 36.26%. Its vapour density is 44. Find the Empirical and molecular formula of the compound. (H = 1, C = 12,0 = 16)

An organic compound containing carbon, hydrogen and oxygen gave the following percentage composition : C = 40.68%, H = 5.08% The vapour density of the compound is 59. Calculate the molecular formula of the compound.

An organic substance containing carbon, hydrogen and oxygen gave following percentages, C= 40.68%, H_(2) = 5.085% and O_(2) = 54.22%. The vapour density of the compound is 59. Calculate the molecular formula of the compound.

A hydrocarbon contain 80% C . The vapour density of compound in 30 . Molecular formula of compound is :-

A hydrocarbon contain 80% C . The vapour density of compound in 30 . Molecular formula of compound is :-

An organic compound on analysis gave the following percentage composition : C = 57.8%, H = 3.6% and the rest is oxygen. The vapour density of the compound was found to be 83. Find out the molecular formula of the compound

An aromatic organic compound has the following composition by weight c = 77.42% H = 7.53% N = 15.05% The vapour density of the compound is 46.5. Find the molecular formula of the compound.

A carbon compound contains 12.8% Carbon, 2.1% Hydrogen, 85.1% Bromine. The molecular weight of the compound is 187.9. Calculate the molecular formula.