`C(20,0)+C(20,1)+C(20,2)+...+C(20,10)`

The expression C(20,0).C(20,1)+C(20,1).C(20,2)+...+C(20,19).C(20,20) equals C(n,r), where r>[n/2].The value of r is ..............{where [ ] is the step function}.

The sum of the series C(20,0)-C(20,1)+C(20,2)-C(20,3)+...-...+C(20,10) is

20 C_(0)+20 C_(1)+20 C_(2)+.. .+20 C_(10) =

The sum of the series .^(20)C_(0)-.^(20)C_(1)+ .^(20)C_(2)-.^(20)C_(3)+...-.+ .^(20)C_(10) is -

The sum of series ^(20)C_0-^(20)C1+^(20)C2-^(20)C3++^(20)C 10 is

The sum of the series .^(20)C_(0)-.^(20)C_(1)+ .^(20)C_(2)-.^(20)C_(3)+...-.+ .^(20)C_(10) is -

The sum of series .^(20)C_0-^(20)C_1+^(20)C_2-^(20)C_3+....+^(20)C _10 is

The sum of series: ""^(20)C_(0)-""^(20)C_(1)+""^(20)C_(2)-""^(20)C_(3)+ . . . +""^(20)C_(10) is:

Find the value of .^(20)C_(0) - .^(20)C_(1)+ .^(20)C_(2) - .^(20)C_(3) +"……"-"....." + .^(20)C_(10) . is

The sum of the series 20C_(0)-^(20)C_(1)+^(20)C_(2)-^(20)C_(3)+...-...+^(20)C_(10) is: