If the difference of the roots of `x^2-p x+q=0` is unity, then
a) `p^2+4q=1` b) `p^2-4q=1` c) `p^2+4q^2=(1+2q)^2` d) `4p^2+q^2=(1+2p)^2`

If the difference of the roots of x^(2)-px+q=0 is unity,then p^(2)+4q=1b .p^(2)-4q=1c*p^(2)+4q^(2)=(1+2q)^(2)d4p^(2)+q^(2)=(1+2p)^(2)

If the difference of the roots of the equation x^2-px+q=0 is 1, then show that p^2+4q^2= (1+2q)^2 .

If the difference of the roots of the question ,x^(2)+px+q=0"be unity, then"(p^(2)+4q^(2)) equals to :

If the difference of the roots of the question ,x^(2)+px+q=0"be unity, then"(p^(2)+4q^(2)) equals to :

If difference of roots of the equation x^(2)-px+q=0 is 1, then p^(2)+4q^(2) equals-

If the difference of the roots of the equation, x^2+p x+q=0 be unity, then (p^2+4q^2) equal to: (1-2q)^2 (b) (1-2q)^2 4(p-q)^2 (d) 2(p-q)^2

If the difference of the roots of the equation,x^(2)+px+q=0 be unity,then (p^(2)+4q^(2)) equal to: (1-2q)^(2)(b)(1-2q)^(2)4(p-q)^(2)(d)2(p-q)^(2)

If the difference of the roots of the equation,x^(2)+px+q=0 be unity,then (p^(2)+4q^(2)) equals to: (1+1q)^(2) b.(1-2q)^(2) c.4(p-q)^(2) d.2(p-q)^(2)

If the difference of the roots of the quadratic equation x^(2)-px+q=0 be 1, then prove that p^(2)+4q^(2)=(1+2q)^(2) .

If p and q are the roots of the equation x^2-p x+q=0 , then (a) p=1,\ q=-2 (b) p=1,\ q=0 (c) p=-2,\ q=0 (d) p=-2,\ q=1