1 mol of a gaseous aliphatic compound `C_nH_(3n)O_m` is completely burnt in an excess of oxygen. The contraction in volume in (assume water gets condensed out ):

1 ml of gaseous aliphatic compound C_(n) H_(3n) O_(m) is completely burnt in an excess of O_(2) . The contraction in volume is

1 ml of gaseous aliphatic compound C_(n) H_(3n) O_(m) is completely burnt in an excess of O_(2) . The contraction in volume is

When a gaseous olefinic hydrocarbon is burnt completely in excess of O_(2) , a contraction in volume equal to double to the volume of hydrocarbon is noticed then hydrocarbon will be

When a gaseous olefinic hydrocarbon is burnt completely in excess of O_(2) , a contraction in volume equal to double to the volume of hydrocarbon is noticed then hydrocarbon will be

1 volumes of gaseous compound consistin C, H, O on complete combustion in presence of 2.5 volume of the formula of the compound if all measurements are made at STP ?

50 ml Toluene [C_(6)H_(5)CH_(3)(g)] undergoes combustion with excess of oxygen. Calculate the volume contraction.

16 " mL of " a gaseous compound C_(n)H_(3n)O_(m) was mixed with 60 " mL of " O_2 and sparked. The gas mixture on cooling occupied 44 mL. After treatment with NaOH solution, the volume of gas remaining was 12 mL. Deduce the formula of the compound.

16 " mL of " a gaseous compound C_(n)H_(3n)O_(m) was mixed with 60 " mL of " O_2 and sparked. The gas mixture on cooling occupied 44 mL. After treatment with NaOH solution, the volume of gas remaining was 12 mL. Deduce the formula of the compound.