If the specific conductane of `1 M H_(2)SO_(4)` solution is `26xx10^(2)S cm^(2)`, then the equivalent conductivity would be

If the specific conductance of 1 M H_(2)SO_(4) solution is 26xx10^(-2)S cm^(2) , then the equivalent conductivity would be

Specific conductivity of 0.01N H_(2)SO_(4) solution is 6 xx 10^(-3) S cm^(-1) . Its molar conductivity is

Conductivity of 0.12 M CuSO_(4) solution at 298 K is 1.8 xx 10^(-2) S cm^(-1) Calculate its equivalent conductivity

At a given temperature, specific conductance of 0.001(M) acetic acid solution is 5xx10^(-5)"S.cm"^(-1) and equivalent conductivity at infinite dilution is "390.5 S.cm"^(2).mol"^(-1) . What is the value of dissociation constant of acetic acid at the same temperature.

Conductivity of 0.12 M CuSO_(4) solution at 298 K is 1.8 xx 10^(-2) S cm^(-1) Calculate its equivalent conductivty

The specific conductance of 0.036 M KBr solution is 5.40 xx 10^(-4) S cm^(-1) . Find the molar conductivity of the solution.

The specific conductance of a 0.12 N solution of an electrolyte is 2.4xx10^(-2) S cm^(-1) . Calculate its equivalent conductance.

The specific conductance of a 0.12 N solution of an electrolyte is 2.4xx10^(-2) S Cm^(-1) . Calculate its equivalent conductivity,

Ionic conductance of H^(+) and SO_(4) are x and yS cm^(2) mol^(-1) . Hence equivalent conductivity of H_(2)SO_(4) is