`|(x-3)|+2|(x+1)|=4`

|x-3|+2|x+1|=4

lim_ (x rarr (1) / (2)) ((8x-3) / (2x-1) - (4x ^ (2) +1) / (4x ^ (2) -1))

If |(3,2),(1,x)|-|(2x,3),(-2,1)|=|(4.1,1),(2,1)|^(2) , then x=______

((x + 2) (x ^ (3) -2x + 1)) / (4 + 3x-x ^ (3))> = 0

Lt_(x to oo)((8x-3)/(2x-1)-(4x^(2)+1)/(4x^(2)-1))=

underset(x to 1//2)lim {(8x-3)/(2x-1)-(4x^(2)+1)/(4x^(2)-1)}=

lim_(x to 1/2)((8x-3)/(2x-1)-(4x^(2)+1)/(4x^(2)-1)) .

Check whether the following are quadratic equations : (1) (x-2)^(2)+1=2x-3 (2) x(x+1)=8=(x+2)(x-2) (3) x(2x+3)=x^(2)+1 (4) (x+2)^(3) = x^(3)-4

If |(x+1,x-1),(x-3,x+2)|=|(4,-1),(1,3)| , then write the value of x .