Solve the differential equation `(x^2+y^2)dx+2xydy=0`.

Solve the differential equations: (x^2-y^2)dx+2xydy=0, y(1)=1

Consider the differential equation (x^2-y^2)dx+2xydy=0 . Write the order and degree of differential equation.

Consider the differential equation (x^2-y^2)dx+2xydy=0 . Show that the differential equation is homogeneous.

Solve the differential equation: dy=x(x^2-2y)dx

The curve amongst the family of curves, represented by the differential equation (x^2-y^2)dx+2xydy=0 which passes through (1,1) is

The curve amongst the family of curves, represented by the differential equation (x^2-y^2)dx+2xydy=0 which passes through (1,1) is

The curve amongst the family of curves, represented by the differential equation (x^2-y^2)dx+2xydy=0 which passes through (1,1) is

The curve amongst the family of curves, represented by the differential equation (x^2-y^2)dx+2xydy=0 which passes through (1,1) is

Solve the differential equation : (x^2y + x^2)dx + (xy^2 - y^2) dy = 0