Solve for `z : z^2-(3-2i)z+(5i-5)dot`

Solve the following for z: z^(2)-(3-2i)z=(5i-5)

Solve the equation |z+1|=z+2(1+i)dot

Let z be a complex number satisfying (3+2i) z +(5i-4) bar(z) =-11-7i .Then |z|^(2) is

Let z_(1), z_(2), z_(3) be the roots of iz^(3) + 5z^(2) - z + 5i = 0 , then |z_(1)| + |z_(2)| + |z_(3)| = _____________.

If conjugate of a complex number z is (2+5i)/(4-3i) , then |Re(z) + Im(z)| is equal to ____________

Radius of the circle z bar(z) + (2 + 5.5 i) z + (2-5.5 i) bar(z) + 4 = 0 is ___________

The least value of |z-3-4i|^(2)+|z+2-7i|^(2)+|z-5+2i|^(2) occurs when z=

The least value of |z-3-4i|^(2)+|z+2-7i|^(2)+|z-5+2i|^(2) occurs when z=

The least value of |z-3-4i|^(2)+|z+2-7i|^(2)+|z-5+2i|^(2) occurs when z=