`( log_2 10).(log_2 80) - (log_2 5).(log_2 160)` is equal to:

2^(2-log_2 5)

Prove that : (log_(2)10)(log_(2)80)-(log_(2)5)(log_(2)160)=4 .

Evaluate log_2 log_2 16

The value of log_(2)20log_(2)80-log_(2)5log_(2)320 is equal to a)5 b)6 c)7 d)8

A denotes the product xyz where x,y and z satisfy log_3 x= log5-log7 and log_5 y=log7-log 3 and log_7 z=log 3-log5 B denotes the sum of square of solution of the equation, log_2(log_2 x^6 - 3) - log_2(log_2 x^4 - 5) = log_2 3 C denotes characterstio of logarithm log_2 (log_2 3)-log_2 (log_4 3)+log_2(log_4 5)-log_2(log_6 5)+log_2 (log_6 7)-log_2 (log_6 3) The valuo of A+B+C is equal to

Prove that log_2 log_2 log_2 16=1

log_(10)3+log_(10)2-2log_(10)5

3log_(2)5+log_(2)10-log_(2)625

If log_10 2 = 0.3010 is given, then log_2 10 is equal to :