Supposing Newton's law of gravitation for gravitation forces `F_(1)` and `F_(2)` between two masses `m_(1)` and `m_(2)` at positions `r_(1)` and `r_(2)` read
where `M_(0)` is a constant of dimension of mass, `r_(12) = r_(1) - r_(2)` and `n` is a number. In such a case,

Supposing Newton's Law of gravitation for gravitation forces F_1 and F_2 between two masses my and m, at positions r_1 and r_2 read F_1=-F_2=-(r_(12))/(r_(12^3))GM_0^2((m_1m_2)/(M_0^2))^(2) where M_0 is a constant of dimension of mass, r_(12) =r_1 -r_2 and n is a number. In such a case,

Supposing Newton's law of gravitation for gravitation force F_(1) and F_(2) between two masses m_(1) and m_(2) at positions r_(1) and r_(2) read F_(2)=-F_(2)=(r_(12))/(r_(12)^(3))GM_(0)^(2)((m_(1)m_(2))/(M_(0)^(2)))^(n) where M_(0) is a constant dimension of mass, r_(12)=r_(1)-r_(2) and n is number. In such a case.

Supposing Newton's law of gravitational for gravitation fores vecF_1 and vecF_2 between two masses m_1 and m_2 at positions vecr_1 and vecr_2 read vecF_1 = - vecF_2 = - (vecr_12)/(r_12^3) GM_0^1((m_1m_2)/(m_0^2))^n where M_0 is a constant of dimension of mass. vecr_12 = vecr_1 - vecr_2 and n is a number. In such a case

Gravitational force, F=Gm_(1)m_(2)//r.

Position vector of centre of two particles of masses m_(1) and m_(2) whose position vectors r_(1) and r_(2) then r_(cm) ?

The gravitional force between two point masses m_(1) and m_(2) at separation r is given by F=k (m_(1)m_(2))/r^(2) The constant k

Write an expression for the gravitational force of attraction between two bodies of masses m_1 and m_2 separated by a distance r .

The gravitational force between two point masses m_(1) and m_(2) at separation r is given by F = k(m_(1) m_(2))/(r^(2)) The constant k doesn't

The gravitational force F between two masses m_(1) and m_(2) separeted by a distance r is given by F = (Gm_(1)m_(2))/(r^(2)) Where G is the universal gravitational constant. What are the dimensions of G ?