In the given figure, `angle 1 = angle 2 and (AC)/(BD)=(CB)/(CE)` prove that `Delta ACB~ Delta DCE`.

In the given figure, in Delta ABC, angle B= angle C and BD= CE . Prove that DE||BC .

In the given figure , BC = CE and angle 1 = angle 2. Prove that : Delta GCB = Delta DCB .

In the given figure, (QT)/(PR) = (QR)/(QS) and angle 1 = angle 2 Prove that Delta PQS ~ Delta TQR .

In the given figure, ABC is a triangle with /_EDB = /_ACB . Prove that DeltaABC ~ DeltaEBD . If BE = 6 cm, EC = 4 cm, BD = 5 cm and area of Delta BED = 9 cm^2 . Calculate the : area of Delta ABC

In the given figure of AD = CB then prove that AC = BD

In the given figure, angle ACB=90^(@) and CD bot AB . Prove that CD^(2)=BD*AD

Delta ACB ~= Delta DFE . Find angle F

In the given figure, (AD)/(DB)=(AE)/(EC) and angle ADE=angle ACB . Prove that Delta ABC is an isosceles triangle.

In the given figure, ABD is a triangle right angled at A and AC bot BD . Show that AD^(2)= BD*CD

In the given figure, if angleD = angleC, then it is true that triangle ADE ~ triangle ACB? Why?