2+x

det [[x + 4,2x, 2x2x, x + 4,2x2x, 2x, x + 4]]

Solve : |(x+4, 2x,2x),(2x , x+4, 2x),(2x, 2x, x+4)| = 0

|[x+lambda, 2x, 2x], [2x, x+lambda, 2x], [2x, 2x, x+lambda]| =(5x+ lambda)(lambda-x)^(2)

|(x+4, 2x, 2x),(2x, x +4, 2x),(2x, 2x ,x+4)| = (5x + 4)(4 - x)^(2) .

Prove that: |[x+4,2x,2x],[2x,x+4,2x],[2x,2x,x+4]|=(5x+4)(4-x)^2 .

By using properties of determinants, show that : |[x+4,2x,2x],[2x,x+4,2x],[2x,2x,x+4]| = (5x+4)(4-x)^2

By using properties of determinats. Prove that- |(x+4,2x,2x),(2x,x+4,2x),(2x,2x,x+4)| = (5x + 4) (x - 4)^2

|[x+4,2x,2x] , [2x,x+4,2x] , [2x,2x,x+4]|=(5x+4)(x-4)^2

|{:(x+4,2x,2x),(2x,x+4,2x),(2x,2x,x+4):}|=(5x+4)(x-4)^2