`SiCl_(4)+4H_(2)O to X+4HCl` 'X' on heating upto `1000^(0)C` 'Y' on treating with HF, the final product obtained is

Hydrolysis of SiCl_(4) gives compound 'X' and HCl on heating to 1000^(@)C 'X' loses water and forms 'Y'. Identify 'X' and 'Y' respectively.

Hydrolysis of SiCl_(4) gives compound 'X' and HCl on heating to 1000^(@)C 'X' loses water and forms 'Y'. Identify 'X' and 'Y' respectively.

Sodium metal was heated in excess of air and then product was treated with cold dilute H_(2)SO_(4) . The final products obtained are

SiCl_(4) on hydrolysis forms 'X' and HCl. Compound 'X' loses water at 1000^(@)C and gives 'Y' compounds 'X' and 'Y' respectively are

SiCl_(4) overset(H_(2)O)(to) X overset("Heat")(to) Y overset(NaOH)(to) Z find X,Y,Z.

A nitrile X is treated with LiAIH_(4) to obtain compound Y(C_(2)H_(7)N) . In a separate reaction X is hydrolysed in an acid medium to obtain Z. The product obtained after mixing Y and Z will be :

A nitrile X is treated with LiAIH_(4) to obtain compound Y (C_(2)H_(7)N) . In a separate reaction X is hydrolyzed in an acid medium to obtain Z. The product obtained after mixing Y and Z will be