The heat of combustion of ethanol was determined in a bomb calorimeter and was found to be `-670.48kcal mol^(-1)` at `25^(@)C`. What will be `DeltaU` for the same reaction at `298K` ?

What is heat of combustion ? How is it determined using bomb calorimeter ?

The heat of combustion of ethanol determinal in a bomb calorimeter is -670.48 K. Cals "mole"^(-1) at 25^(@)C . What is Delta H at 25^(@)C for the reaction :-

The heat of combustion of ethanol determinal in a bomb calorimeter is -670.48 K. Cals "mole"^(-1) at 25^(@)C . What is Delta H at 25^(@)C for the reaction :-

The heat of combustion of ethanol in a bomb calorimeter is -670 .48 k Cal mol^(-1) at 25^(@)C . What is DeltaE at 25^(@) C for the reaction ?

The heat of combustion of ethanol determined by a bomb calorimeter is -670.48 kcal mol^-1 at 25^@C . What is triangleU at 25^@C for the reaction, C_2H_5OH(l)+3 O_2(g)rarr2CO_2+3H2O(g) is:

The heat of combusion of benzne determined in a bomb calorimeter is -870Kcal mol^(-1) at 298 K . The value of DeltaE for the reaction is

The heat of combusion of benzne determined in a bomb calorimeter is -870Kcal mol^(-1) at 298 K . The value of DeltaE for the reaction is