The equation of the radical axis of the system of coaxial circles `x^2 + y^2 + 2ax + 2by + c + 2lambda(ax-by + 1) = 0` is

Find the equation of the radical axis of the following circles. x^2 + y^2 + 2x + 4y + 1 = 0. x^2+y^2 + 4x + y = 0

Find the equation of the radical axis of the following circles. x^2 + y^2 -2x - 4y -1 = 0. x^2 + y^2 - 4x - 6y + 5 = 0 .

Find the equation of the radical axis of the following circles. x^2+y^2+2x+4y+1=0 x^2+y^2+4x+y=0

Find the equation of the radical axis of the following circles. x^2+y^2+2x+4y+1=0 x^2+y^2+4x+y=0

The equation to the line joining the centres of the circles belonging to the coaxial system of circles 4x^(2) + 4y^(2) - 12x + 6y - 3 + lambda (x + 2y - 6) = 0 is

Find the equation of the radical axis of the following circles. x^2+y^2-2x-4y-1=0 x^2+y^2-4x-6y+5=0

Find the equation of the radical axis of the following circles. x^2+y^2-2x-4y-1=0 x^2+y^2-4x-6y+5=0

Find the equation of the radical axis of the following circles. x2+y2+3x+2y+1=0 & x2+y2+3x+4y+2=0 is