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The expression, (1+sec2theta)(1+sec4thet...

The expression, `(1+sec2theta)(1+sec4theta)(1+sec8theta)` is equal to -

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(1-sec8 theta)/(1-sec4 theta)

sec4theta - sec2theta=2

(1+sec theta)/sec theta=

sec^(4) theta - sec^(2) theta is equal to

(1- sec 8 theta )/( 1- sec 4 theta ) =

(1 + sec 2 theta)(1 + sec 2^(2) theta)(1 + sec 2^(3) is equal is

sec^(4)theta - sec^(2)theta equals

1+(tan^(2)theta)/((1+sec theta))=sec theta