A and B throw a pair of die turn by turn. The first to throw 9 is awarded a prize. If A starts the game, show that the probability of A getting the prize is `9/7`

A and B throw a pair of die turn by turn. The first to throw 9 is awarded a prize. If A starts the game, show that the probability of A getting the prize is 9/17

Two persons A and B take turns in throwing a pair of dice. The first person to throw 9 from both will get the prize. If A throws first then the probability of B winning the prize is -

Two persons A and B take turns in throwing a pair of dice. The first person to throw 9 from both dice will be awarded the prize. If A throws first, then the probability that B wins the game is 9//17 b. 8//17 c. 8//9 d. 1//9

Two persons A and B take turns in throwing a pair of dice. The first person to throw 9 from both dice will be awarded the prize. If A throws first, then the probability that B wins the game is 9//17 b. 8//17 c. 8//9 d. 1//9

A and B alternately throw with a pair of dice. Who gets a sum of 7 points 1 th will win the game.If A starts the game,the probability of his winning is

In a single throw of a die, find the probability of getting: 8

A and B take turns in throwing two dice, the first to throw 9 being awarded the prize. Show that their chance of winning are in the ratio 9:8.

A and B take turns in throwing two dice, the first to throw 9 being awarded the prize. Show that their chance of winning are in the ratio 9:8.