Find the equation of the normal to `y=2x^3-x^2+3` at (1,4).

Consider the curve x^(2/3)+y^(2/3)=2 Find the equation of the normal at the point (1,1).

Find the equation of the normal to y = x^(2) -2x that is parallel to x + 4y -1 = 0

Find the equation of the normal to the curve y = x^3 at the point (2,1).

Find the equation of the normal to y=x^(3)-3x, which is parallel to 2x+18y=9

Find the equation of normal to y = x^(3) -3x that is parallel to 2x + 18y - 9 = 0

Find the equations of the normal to the curve y=x^3+2x+6 which are parallel to the line x+14 y+4=0.

Find the equation of the normals to the curve y=x^3+2x+6 which are parallel to the line x + 14 y + 4 = 0 .