`lim(x->a_-) {(|x|^3)/a-[x/a]^3} ,(a < 0)`, where `[x]` denotes the greatest integer less than or equal to `x` is equal to:

lim(x rarr a_(-)){(|x|^(3))/(a)-[(x)/(a)]^(3)},(a<0) where [x] denotes the greatest integer less than or equal to x is equal to:

(lim)_(x->3)x+3

lim_(x rarr1)(|x^(3)-x|)/(x-x^(3))3lim

Prove that lim_(x->3^+) x/[[x]] != lim_(x->3^-) x/([x])

lim_(x rarr2^(+))(([x]^(3))/(3)-[(x)/(3)]^(3)) is

lim_ (x) rarr (2 ^ (+)) (([x] ^ (3)) / (3) - [(x) / (3)] ^ (3)) is

lim_(x rarr2^(+))(([x]^(3))/(3)-[(x)/(3)]^(3)) is

lim_(x rarr2^(+))(([x]^(3))/(3)-[(x)/(3)]^(3))

lim_(x rarr oo)((x-3)/(x+3))^(x+3)