A capacitor has capacitance `10muF` audit is charged to a potential `150V`. A second capacitor has a capacitance of `20 muF` and it is charged to a potential of `300V`. After charging, the two capacitors are connected in parallel with their same polarity plates together by using wires of negligible capacitance. Find how much energy is dissipated?

A capacitor of capacitance 50 muF is charged to a potential of 1,000 V. Calculate the energy stored in the capacitor.

Find the energy stored in a capacitor of capacitance 100muF when it is charged to a potential difference of 20 V.

Find the energy stored in a capacitor of capacitance 100muF when it is charged to a potential difference of 20 V.

Find the energy stored in a capacitor of capacitance 100muF when it is charged to a potential difference of 20 V.

A parallel plate capacitor of capacitances C is connected to a battery to charge it to a potential V. Similarly, another capacitor of capacitance 2C is charged to a potential 2V. Now the batteries are removed, and the two capacitors are connected in parallel by joining the positive plate to one with the negative plate of the other. Find out the final energy of the system.

A capacitor of capacitance of 2muF is charged to a potential difference of 200V , after disconnecting from the battery, it is connected in parallel with another uncharged capacitor. The final common potential is 20V then the capacitance of second capacitor is :

A 2muF capacitor is charged to a potential of 20V. Another 3muF uncharged capacitor is connected in parallel with the first capacitor. What would be the terminal potential difference of the combination? Find out the charges on the two capacitors?

Two capacitors of capacitance 10 muF and 20 muF are charged to potential 20 V and 10 V respectively. If they are connected to share charges, then loss of energy is