The angles of a triangle are in the ratio, `1:2:7`. Prove that the ratio of the longest and smallest side is `(sqrt(5)+1): (sqrt(5)-1)`.

If the angles of a triangle are in the ratio 1:2:7 , then the ratio of the longest side to the smallest side is

The angle of a triangle are in the ratio 1 : 2 : 7, prove that the ratio of the greatest side to the least side is (sqrt(5)+1):(sqrt(5)-1) .

The angles of a triangle are in the ratio 1:2:3 . What is the sine of the smallest angle?

If the angles of a triangle are in the ratio 7:2:1, then prove that the ratio of smallest side to the largest side is sqrt(5)-1:sqrt(5)+1

If the angles of a triangles are in ratio 1: 2: 7 Then prove that the greatest side to the least side is ( sqrt5 + 1) : ( sqrt5-1)

If the angles of a triangle are in the ratio 4:1:1 , then the ratio of the longest side to the perimeter is

If the angles of a triangles are in the ratio 1: 5: 6 then the ratio of its sides is

The angles of a triangle are in the ratio 3:5:10. Then the ratio of the smallest side to the greatest side is

The angless of a triangle are in the proportion 7:2:1, prove that the ratio of the least side to the greatest is 3-sqrt(5):2.