For any three vectors `veca,vecb&vec c` prove that `(vecbxxvec c)xx(vec cxxveca)=[veca vecb vec c] vec c`

For any three vectors veca,vecb,vec(c) prove that [vecbxxvec(c)" "vec(c)xxveca" "vecaxxvecb]=[vec(a)" "vecb" "vec(c)]^(2)

For any three vectors veca, vec b, vec c prove that (vec a + vec b)+ vec c = vec a + (vec b + vec c)

Prove that : veca*(vecb+vec c)xx(veca+2vecb+3vec c)=[veca vecb vec c]

Prove that veca*(vecb+vec c)xx (veca+3vecb+2vec c)=-(veca vecb vecc )

Let veca, vecb and vec c be any three vectors; then prove that [[vecaxxvecb, vecbxxvecc, veccxxveca]] = [[veca, vecb, vecc]]^2

Show that for any three vectors veca , vec b and vec c [ vec a + vec b, vecb + vec c , vec c + vec a ] =2[vec a , vec b , vecc] .

For any two vectors vec a\ a n d\ vec b prove that | vec axx vec b|^2=| (veca. veca , veca. vecb),(vecb.veca ,vecb.vecb)|

For any two vectors vec a\ a n d\ vec b prove that | vec axx vec b|^2=| (veca. veca , veca. vecb),(vecb.veca ,vecb.vecb)|

If veca+vecb+vec(c)=vec0 , then prove that vecaxxvecb=vecbxxvec(c)=vec(c)xxveca .

If [veca+vecb, vecb+vec c, vec c+veca]=8 then [veca, vecb, vec c] is