`(dy)/(dx)=sinx/e^y`

If y=e^(sinx)+(tanx)^(x)," prove that "(dy)/(dx)=e^(sinx)cosx+(tanx)^(x)[2x" cosec "2x+log tanx].

Degree and order xy(d^(2)y)/(dx^(2))+((dy)/(dx))^(3)-y(dy)/(dx)=sinx

(dy)/(dx ) + 2y =sinx

(dy)/(dx)+(y)/(x)=sinx

Solve sinx*(dy)/(dx)=y*lny if y=e, when x=pi/2

(dy)/(dx) + 2y = e ^(-2x) sinx , given that y=0 when x = 0

Solve the following initial value problem: (dy)/(dx)+2y=e^(-2x)sinx ,\ y\ (0)=0

Let y=y(x) be solution of the following differential equation e^(y)(dy)/(dx)-2e^(y)sinx+sinxcos^(2)=0,y((pi)/(2))=0 If y(0)=log_(e)(alpha+betae^(-2)) , then 4(alpha+beta) is equal to _____.

If y=2sinx ,then (dy)/(dx) will be