A complex number is given by `z=(1+2i)/(1-(1-i)^(2))`
What is the modulus of z ?

A complex number is given by z=(1+2i)/(1-(1-i)^(2)) What is the principal argument of z?

Consider the complex number z_1 = 3+i and z_2 = 1+i .What is the conjugate of z_2 ?

Consider the complex number z=(1+3i)/(1-2i) . Write z in the form a+ib

If Z=1+i , where i=sqrt(-1) , then what is the modulus of Z+(2)/(Z) ?

Consider the complex number z=(2+i)/((1+i)(1-2i)) (i) Express z in the form a+ib .

If complex number z lies on the curve |z-(-1+i)|=1, then find the locus of the complex number w=(z+i)/(1-i),i=sqrt(-1)1

For complex numbers z_1 = 6+3i, z_2=3-I find (z_1)/(z_2)